20210403, 02:21  #1 
Aug 2002
10000010011000_{2} Posts 
April 2021

20210403, 05:17  #2  
Oct 2017
171_{8} Posts 
Quote:
If my understanding is correct, "seven steps" has to be replaced by "seven spins". What do you mean? 

20210404, 08:26  #3  
Jul 2015
2^{2}·7 Posts 
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20210404, 12:33  #4  
"Ed Hall"
Dec 2009
Adirondack Mtns
100B_{16} Posts 
Quote:


20210404, 13:32  #5  
Oct 2017
79_{16} Posts 
Quote:
 See #2: seven spins, not seven steps  The wheel turns anticlockwise. Or the arrow turns clockwise.  What does mean: "there is a set of unwinnable numbers"? "There is at least one set" or "there is exactly one set"? 

20210404, 13:39  #6  
Feb 2017
Nowhere
2^{4}×11×29 Posts 
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I also note Quote:


20210404, 13:41  #7 
Oct 2017
11^{2} Posts 
If I replace "clockwise" by "anticlockwise" it is possible to confirm the three unwinnable sets of the example.

20210404, 15:28  #8  
Jan 2017
2^{3}·3·5 Posts 
From the example it seems clear that the intended meaning is that the arrow moves clockwise around the wheel.
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20210404, 20:11  #9 
Oct 2017
11^{2} Posts 
I'm pretty sure the intended meaning is "infinitesimally small". That is, the phrasing is only intended to indicate which of the two sectors is the one removed, not meant to imply that any finite multiple of it would ever reach the size of a full sector.[/QUOTE]
That's the only interpretation making sense. Otherwise the puzzlemaster had to concretize the "a little less than one number"  0,9999 or so. q will become very big. 
20210405, 13:22  #10  
Feb 2017
Nowhere
2^{4}·11·29 Posts 
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20210405, 15:21  #11  
"Kebbaj Reda"
May 2018
Casablanca, Morocco
94_{10} Posts 
Quote:
In example 1 of the wheel with q = 5: 1 round removes the 5 2nd round remove the 3 3rd round removes the 8 and remains 1,2,3,6,7 The next round is the 7 which will jump. .... But what I don't understand is example 2. "a set of k numbers unwinnable"? Last fiddled with by Kebbaj on 20210405 at 15:26 

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